The distance of the image appears at the distance x in the equation (1/distance of focus)-(1/Distance of object)=(1/x). The magnification of the object is equal to (height of the image)/(height of the object). The negative value shows that the image is inverted. The magnification is also equal to -(distance of image)/(distance of object).
Sunday, March 15, 2009
Spoons
I was eating a cup of yogurt when I was staring into the spoon. I appeared upside down in the image. The spoon acted like a concave mirror and produced a real inverted image.
The distance of the image appears at the distance x in the equation (1/distance of focus)-(1/Distance of object)=(1/x). The magnification of the object is equal to (height of the image)/(height of the object). The negative value shows that the image is inverted. The magnification is also equal to -(distance of image)/(distance of object).
The distance of the image appears at the distance x in the equation (1/distance of focus)-(1/Distance of object)=(1/x). The magnification of the object is equal to (height of the image)/(height of the object). The negative value shows that the image is inverted. The magnification is also equal to -(distance of image)/(distance of object).
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